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NEW QUESTION: 1
Your company has offices in Miami, Singapore and Montreal. An Active Directory site exists for each office.
You have an Exchange Server 2013 organization that contains a server in each site. Each server has the Mailbox server role and the Client Access Server role installed.
All users connect to the Miami servers to retrieve the public folder hierarchy.
You need to create several public folders on the server in the Singapore office to meet the following requirements:
Ensure that the public folders are available if a single Mailbox server fails.
Ensure that the users in the Singapore office connect to their local server to retrieve the public folder hierarchy.
Which actions should you perform? (Each correct answer presents part of the solution. Choose all that apply.)
A. Run the Add-MailboxDatabaseCopycmdlet.
B. Run the Set-PublicFolderDatabasecmdlet.
C. For each public folder mailbox, run the Set-Mailbox cmdlet and specify the -defaultpublicfoldermailbox parameter.
D. Create a new public folder mailbox.
E. For each mailbox in the Singapore office, run the Set-Mailbox cmdlet and specify the -defaultpublicfoldermailbox parameter.
F. Create a new public folder database.
Answer: A,D,E
Explanation:
Public Folders Public folders can also be used as an archiving method for distribution groups. When you mail-enable a public folder and add it as a member of the distribution group, email sent to the group is automatically added to the public folder for later reference.
Public folders are designed for shared access and provide an easy and effective way to collect, organize, and share information with other people in your workgroup or organization.
Public folders help organize content in a deep hierarchy that's easy to browse. Users will see the full hierarchy in Outlook, which makes it easy for them to browse for the content they're interested in.
Public folder architecture In Exchange 2013, public folders were re-engineered using mailbox infrastructure to take advantage of the existing high availability and storage technologies of the mailbox database. Public folder architecture uses specially designed mailboxes to store both the public folder hierarchy and the content. This also means that there's no longer a public folder database. High availability for the public folder mailboxes is provided by a database availability group (DAG).
NOT B In Exchange 2013, public folders were re-engineered using mailbox infrastructure to take advantage of the existing high availability and storage technologies of the mailbox database. Public folder architecture uses specially designed mailboxes to store both the public folder hierarchy and the content. This also means that there's no longer a public folder database There is no database-level setting in Exchange 2013. Exchange 2013 has a mailbox-level ability to specify the public folder mailbox, but by default Exchange auto-calculates the peruser hierarchy mailbox.
NOT E http://technet.microsoft.com/en-us/library/aa997225(v=exchg.141).aspx Use the Set-PublicFolderDatabase cmdlet to set attributes of public folder databases (Exchange Server 2010) There's no longer a public folder database in Exchange Server 2013. There is no database-level setting in Exchange 2013. Exchange 2013 has a mailbox-level ability to specify the public folder mailbox, but by default Exchange auto-calculates the peruser hierarchy mailbox.
NOT F
Need to set it in the Singapore Office.
Miami users still use the Miami servers to connect to the public folder hiearchy.
A
Need to create a public folder mailbox in the Singapore office.
Use the Add-MailboxDatabaseCopy cmdlet to create a passive copy of an existing active
mailbox database.
D
Use the Set-MailboxServer cmdlet to modify attributes on a computer running Microsoft
Exchange Server 2013 with the Mailbox server role installed.
In Exchange 2007 and Exchange 2010, you could specify which users had access to
specific public folders. In Exchange 2013, you can set the default public folder mailbox per
user. To do so, run the Set-Mailbox cmdlet with the DefaultPublicFolderMailbox parameter.
This ensures that the users in the Singapore office connect to their local server to retrieve
the public folder hierarchy.
NEW QUESTION: 2
Examine the following table:
In the table, you deleted the record of Mark Smith. Which of the following will change as a result?
A. Cardinality of the table
B. Degree of the table
C. Attribute of the table
D. Domain of the table
Answer: A
Explanation:
In tables, the number of rows (or tuples) is called the cardinality. When a record (or row) of the table is deleted (or added), the cardinality of the table changes.
Answer A and DWhen a column of the table is changed, the degree (or attribute is changed). The degree of a table refers to the number of columns that a table has. The number of columns contained in a table is referred to by the term degree of the table; if the degree of a table is increased by 1, it means that a new column is added to the table. The degree of the table denotes the number of columns or attributes.
Answer C is incorrect. A Domain is a set of allowable values for one or more attributes. It is also known as the data domain which refers to all the unique values which a data element may contain. The Domain boundary can be defined by rules such as a the data type with an enumerated list of values. Check constraint is also a simple example of defining the boundary of a domain.
NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2014 server. The database contains two tables that have the following definitions:
Global customers place orders from several countries. You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER
JOIN(SELECT CustomerID, ShippingCountry,COUNT(OrderAmount) DESC) AS
OrderAmountFROM OrdersGROUP BY CustomerID, ShippingCountry) AS oON
c.CustomerID = o.CustomerIDORDER BY OrderAmount DESC
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM(SELECT
c.CustomerID, c.CustomerName, o.ShippingCountry, RANK()OVER (PARTITION BY
CustomerIDORDER BY COUNT(o.OrderAmount) ASC) AS RnkFROM Customer cINNER
JOIN Orders oON c.CustomerID = o.CustomerIDGROUP BY c.CustomerID,
c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER
JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY
CustomerIDORDER BY COUNT(OrderAmount) DESC) AS RnkFROM OrdersGROUP BY
CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer cINNER
JOIN(SELECT CustomerID, ShippingCountry,RANK() OVER (PARTITION BY
CustomerIDORDER BY OrderAmount DESC) AS RnkFROM OrdersGROUP BY
CustomerID, ShippingCountry) AS oON c.CustomerID = o.CustomerIDWHERE o.Rnk = 1
Answer: C
Explanation:
Use descending (DESC) ordering.
To order by the number of orders we use ORDER BY COUNT(OrderAmount).
Finally a WHERE close is needed: WHERE o.Rnk = 1
