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NEW QUESTION: 1
Which two are true about management of a far sync instance when using the Data Guard Broker?
A. A far sync instance that has its RedoRoutes property set may not be disabled in the broker configuration.
B. A far sync instance need not exist before adding it to the broker configuration but may not be enabled until created.
C. A far sync instance is in a disabled state in the broker configuration immediately after adding it.
D. Broker management of a far sync instance may only be disabled with the disable configuration DGMGRL command.
Answer: A,C
Explanation:
Explanation/Reference:
A: ADD FAR_SYNC
Adds an existing far sync instance to an Oracle Data Guard broker configuration.
The far sync instance is disabled after creation. You must explicitly enable it before the broker can ship redo to and from it.
B: A far sync instance that has its RedoRoutes property set cannot be disabled.
Incorrect Answers:
D: The far sync instance must already exist before you can add it to a broker configuration.
References: https://docs.oracle.com/database/121/DGBKR/dgmgrl.htm

NEW QUESTION: 2

A. Option B
B. Option C
C. Option A
D. Option D
Answer: C
Explanation:
Explanation
Configuring the debugger to break for first chance exceptions
To change when the debugger breaks, go to Debug->Exceptions...

When you first open this window you will see that there is a tree grid with one column and checkboxes.
* Break when Thrown. This includes a default list of exceptions known by the debugger, grouped by category.
Note: The possible exceptions that could break from this list is determined by the runtime you are debugging.
For example, if you are using managed-only debugging then the debugger will never break for C++, Win32 Exceptions, etc. even if they are configured to break when thrown.
* Checkboxes. If you check the box for a category, then the debugger will break for all First Chance Exceptions while debugging. If you don't want to enable all First Chance Exceptions, you can find the specific exception types that you wish to configure by using the search box.
References:

NEW QUESTION: 3

A. Option D
B. Option B
C. Option C
D. Option A
Answer: A,D

NEW QUESTION: 4
You are testing an application. The application includes methods named CalculateInterest and LogLine. The CalculateInterest() method calculates loan interest. The LogLine() method sends diagnostic messages to a console window.
The following code implements the methods. (Line numbers are included for reference only.)

You have the following requirements:
* The CalculateInterest() method must run for all build configurations.
* The LogLine() method must run only for debug builds.
You need to ensure that the methods run correctly.
What are two possible ways to achieve this goal? (Each correct answer presents a complete solution. Choose two.)
A. Insert the following code segment at line 05:
# if DEBUG
Insert the following code segment at line 07:
# endif
B. Insert the following code segment at line 01:
# region DEBUG
Insert the following code segment at line 10:
# endregion
C. Insert the following code segment at line 01:
# if DEBUG
Insert the following code segment at line 10:
# endif
D. Insert the following code segment at line 05:
# region DEBUG
Insert the following code segment at line 07:
# endregion
E. Insert the following code segment at line 01:
[Conditional("DEBUG")]
F. Insert the following code segment at line 10:
[Conditional("RELEASE")]
G. Insert the following code segment at line 10:
[Conditional("DEBUG")]
Answer: A,G
Explanation:
Explanation: D: Also, it's worth pointing out that you can use [Conditional("DEBUG")] attribute on methods that return void to have them only executed if a certain symbol is defined. The compiler would remove all calls to those methods if the symbol is not defined:
[Conditional("DEBUG")]
void PrintLog() {
Console.WriteLine("Debug info");
}
void Test() {
PrintLog();
}
G: When the C# compiler encounters an #if directive, followed eventually by an #endif directive, it will compile the code between the directives only if the specified symbol is defined. Unlike C and C++, you cannot assign a numeric value to a symbol; the
#if statement in C# is Boolean and only tests whether the symbol has been defined or not.
For example,
# define DEBUG
# if DEBUG
Console.WriteLine("Debug version");
# endif
Reference: http://stackoverflow.com/questions/2104099/c-sharp-if-then-directives-for- debug-vs-release

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