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NEW QUESTION: 1
Answer:
Explanation:
Router>enable
Router#config terminal
Router(config)#hostname Apopka
2) Enable-secret password (cisco10):
Apopka(config)#enable secret cisco10
3) Set the console password to RouterPass:
Apopka(config)#line console 0
Apopka(config-line)#password RouterPass
Apopka(config-line)#login
Apopka(config-line)#exit
4) Set the Telnet password to scan90:
Apopka(config)#line vty 0 4
Apopka(config-line)#password scan90
Apopka(config-line)#login
Apopka(config-line)#exit
5) Configure Ethernet interface (on the right) of router Apopka:
The subnet mask of the Ethernet network 209.165.201.0 is 27. From this subnet mask, we can find out the increment by converting it into binary form, that is /27 = 1111 1111.1111 1111.1111 1111.1110 0000. Pay more attention to the last bit 1 because it tells us the increment, using the formula:
Increment = 2place of the last bit 1 (starts counting from 0,from right to left), in this case increment = 25 = 32.
Therefore:
Increment: 32
Network address: 209.165.201.0
Broadcast address: 209.165.201.31 (because 209.165.201.32 is the second subnetwork, so the previous IP - 209.165.201.31 - is the broadcast address of the first subnet).
-> The second assignable host address of this subnetwork is 209.165.201.2/27 Assign the second assignable host address to Fa0/0 interface of Apopka router:
Apopka(config)#interface Fa0/0
Apopka(config-if)#ip address 209.165.201.2 255.255.255.224
Apopka(config-if)#no shutdown
Apopka(config-if)#exit
6) Configure Serial interface (on the left) of router Apopka:
Using the same method to find out the increment of the Serial network:
Serial network 192.0.2.128/28:
Increment: 16 (/28 = 1111 1111.1111 1111.1111 1111.1111 0000)
Network address: 192.0.2.128 (because 8 * 16 = 128 so 192.0.2.128 is also the network address of this subnet) Broadcast address: 192.0.2.143
-> The last assignable host address in this subnet is 192.0.2.142/28.
Assign the last assignable host address to S0/0/0 interface of Apopka router:
Apopka(config)#interface S0/0/0 (or use interface S0/0 if not successful) Apopka(config-if)#ip address 192.0.2.142 255.255.255.240 Apopka(config-if)#no shutdown Apopka(config-if)#exit
7) Configure RIP v2 routing protocol:
Apopka(config)#router rip
Apopka(config-router)#version 2
Apopka(config-router)#network 209.165.201.0
Apopka(config-router)#network 192.0.2.128
Apopka(config-router)#end
Save the configuration:
Apopka#copy running-config startup-config
Finally, you should use the ping command to verify all are working properly!
NEW QUESTION: 2
What is the main purpose of the planned failover feature?
A. Test a disaster recovery scenario without any downtime on the VM
B. Initiate a disaster recovery procedure when the main site is down
C. Proactively switch from running the regular VM to the replica VM
D. Test the VM in a sandbox without impacting the production environment
Answer: C
Explanation:
Reference:
https://helpcenter.veeam.com/docs/backup/vsphere/planned_failover.html?ver=100
NEW QUESTION: 3
A collection of procedures used to track project artifacts, monitor and control changes on the project:
A. Configuration Management System.
B. Project Management Plan.
C. Collect Requirements
D. Configuration Management Plan.
Answer: A
NEW QUESTION: 4
What is the behavior of the default partitioner?
A. The default partitioner implements a round robin strategy, shuffling the key value pairs to each reducer in turn. This ensures an even partition of the key space.
B. The default partitioner assigns key value pairs to reducers based on an internal random number generator.
C. The default partitioner computes the hash of the key. Hash values between specific ranges are associated with different buckets, and each bucket is assigned to a specific reducer.
D. The default partitioner computes the hash of the key and divides that value modulo the number of reducers. The result determines the reducer assigned to process the key-value pair.
E. The default partitioner computes the hash of the value and takes the mod of that value with the number of reducers. The result determines the reducer assigned to process the key value pair.
Answer: D
Explanation:
The default partitioner computes a hash value for the key and assigns the partition based on this result.
The default Partitioner implementation is called HashPartitioner. It uses the hashCode() method of the key objects modulo the number of partitions total to determine which partition to send a given (key, value) pair to.
In Hadoop, the default partitioner is HashPartitioner, which hashes a record's key to determine which partition (and thus which reducer) the record belongs in.The number of partition is then equal to the number of reduce tasks for the job.
Reference:Getting Started With (Customized) Partitioning