NSE7_NST-7.2 Certification

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NEW QUESTION: 1
展示を参照してください。

このデバイスのNAT設定で、内部インターフェイスと外部インターフェイスを正しく識別しました。
この構成のどの効果が本当ですか？
A. スタティックNAT
B. PAT
C. ダイナミックNAT
D. NAT64
Answer: B

NEW QUESTION: 2

AS64520



Answer:
Explanation:
Check the complete solution below:
Explanation
for EBGP and IBGP lab you have to make correction to the configuration in a router R1.
You have only access to Router R1.
R1 and RA should be neighbors through EBGP.
in R1 you will find this command:
(config-router)#Neighbor 209.165.277.2 remote-as 64525
The ip address here is wrong , delete this command using :
(config-router)#No Neighbor 209.165.277.2 remote-as 64525
And replace it with new command with right ip of RA E0/1 interface
by typing this command:
(config-router)#Neighbor 209.165.201.2 remote-as 64525
R1 and R2 and R3 are neighbors through IBGP, and R1 use the peer-group IBGP to form neighborship between R1 and R2, and between R1 and R3, but actually there issue with the IBGP peer-group commands in R1 You will find in R1 these following commands:
(config-router)#neighbor IBGP peer-group
(config-router)#neighbor IBGP remote-as 64550
(config-router)#neighbor IBGP next-hop-self
(config-router)#neighbor IBGP update-source loopback 0
You must correct the Remote-AS for the Peer-Group to 64520 to form the neighborship correctly.
Watch Out! If you delete the config with " " you also will delete the following lines:
(config-router)#neighbor IBGP peer-group
(config-router)#neighbor IBGP next-hop-self
(config-router)#neighbor IBGP update-source loopback 0
So don't delete the line regarding the "remote-as".
Just replace it with:
(config-router)#neighbor IBGP remote-as 64520
In the Scenario regarding the Lab, they tell you how the routing-table should look if you have done everything right!
So if you routing-table on R1 looks like the one they posted in the scenario you have done everything right and can go on to the next topic.
You have to use the command "#show ip bgp " to show bgp routing table , don't use "#show ip route" command

NEW QUESTION: 3
You have a server named Server1 that runs Windows Server 2012 R2.
You discover that the performance of Server1 is poor.
The results of a performance report generated on Server1 are shown in the following table.

You need to identify the cause of the performance issue.
What should you identify?
A. Excessive paging
B. NUMA fragmentation
C. Driver malfunction
D. Insufficient RAM
Answer: C
Explanation:
Processor: %DPC Time. Much like the other values, this counter shows the amount of time that the processor spends servicing DPC requests. DPC requests are more often than not associated with the network interface.
Processor: % Interrupt Time. This is the percentage of time that the processor is spending on handling Interrupts. Generally, if this value exceeds 50% of the processor time you may have a hardware issue. Some components on the computer can force this issue and not really be a problem. For example a programmable I/O card like an old disk controller card, can take up to 40% of the CPU time. A NIC on a busy IIS server can likewise generate a large percentage of processor activity.
Processor: % User Time. The value of this counter helps to determine the kind of processing that is affecting the system. Of course the resulting value is the total amount of non-idle time that was spent on User mode operations. This generally means application code.
Processor: %Privilege Time. This is the amount of time the processor was busy with Kernel mode operations. If the processor is very busy and this mode is high, it is usually an indication of some type of NT service having difficulty, although user mode programs can make calls to the Kernel mode NT components to occasionally cause this type of performance issue.
Memory: Pages/sec. This value is often confused with Page Faults/sec. The Pages/sec counter is a combination of Pages Input/sec and Pages Output/sec counters. Recall that Page Faults/sec is a combination of hard page faults and soft page faults. This counter, however, is a general indicator of how often the system is using the hard drive to store or retrieve memory associated data.
References:
http: //technet. microsoft. com/en-us/library/cc768048. aspx

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