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NEW QUESTION: 1
You are developing an ASP.NET MVC application. The application includes the following method. Line
numbers are included for reference only.

The application calls the GenerateMessage method before displaying each page.
The GenerateMessage method throws NullReferenceException exceptions.
You need to use Code Contracts to prevent the exceptions.
Which code segment should you insert at line 03?
A. Contract.Assume(userAgent !=null);
B. Contract.Invariant(userAgent !=null);
C. Contract.Ensures(userAgent !=null);
D. Contract.Requires(userAgent !=null);
Answer: D
Explanation:
Explanation/Reference:
Explanation:
There's "Microsoft Code Contracts" where you use syntax like Contract.Requires(obj != null) which gives
you runtime and compile checking. Contract.Requires specifies a precondition contract for an enclosing
method or property.
Incorrect Answers:
A: Contract.Assume instructs code analysis tools to assume that the specified condition is true, even if it
cannot be statically proven to always be true.
C: Contract.Ensures specifies a postcondition contract for the enclosing method or property.
D: Contract.Invariant specifies an invariant contract for the enclosing method or property, and displays a
message if the condition for the contract fails.
References: https://msdn.microsoft.com/en-us/library/system.diagnostics.contracts.contract
(v=vs.110).aspx

NEW QUESTION: 2
Scenario
Refer to the topology. Your company has connected the routers R1. R2. and R3 with serial links. R2 and R3 are
connected to the switches SW1 and SW2, respectively. SW1 and SW2 are also connected to the routers R4 and R5.
The EIGRP routing protocol is configured.
You are required to troubleshoot and resolve the EIGRP issues between the various routers.
Use the appropriate show commands to troubleshoot the issues.









The loopback interfaces on R4 with the IP addresses of 10.4.4.4 /32, 10.4.4.5/32. and 10.4.4.6/32 are not appearing in
the routing table of R5 Why are the interfaces missing?
A. R4 has been incorrectly configured to be in another AS, so it does not peer with R5.
B. The loopback addresses haven't been advertised, and the network command is missing on R4.
C. The interfaces are shutdown, so they are not being advertised.
D. Automatic summarization is enabled, so only the 10.0.0.0 network is displayed.
Answer: A
Explanation:
For an EIGRP neighbor to form, the following must match:
-Neighbors must be in the same subnet
-K values
-AS numbers
-Authentication method and key strings
Here, we see that R4 is configured for EIGRP AS 2, when it should be AS 1.

NEW QUESTION: 3
You have an Exchange Server 2003 organization.
You install an Exchange Server 2010 SP1 Edge Transport server on the network.
You need to ensure that the Edge Transport server can send and receive e-mail messaged
from the internet for the organization.
You configure the Exchange Server 2003 servers to send all e-mail for external recipients to
the Edge Transport servers.
What should you do on the Edge Transport servers?
A. Create and configure a Send connector. Create and configure a Receive connector. Create and configure anAccepted domain.
B. Create an Edge Subscription file. Create and configure a Send connector. Create and configure anAccepted domain.
C. Create and configure a Send connector. Create and configure anAccepted domain. Install the Exchange Server 2010 schema externsions.
D. Create an Edge Subscription file. Create and configure a send connector. Create and configure a Receive connector.
Answer: A

NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
# include <vector>
# include <iostream>
# include <algorithm>
# include <functional>
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
B operator ?(const B &b )const { return B(val ? b.val);}};
ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
B t1[]={1,2,3,4,5,6,7,8,9,10};
B t2[]={1,2,3,4,5,6,7,8,9,10};
vector<B> v1(t1, t1+10);
vector<B> v2(t2, t2+10);
vector<B> v3(10);
transform(v1.begin(), v1.end(), v2.rbegin(), v3.begin(), minus<B>());
for_each(v3.rbegin(), v3.rend(), Out<B>(cout));cout<<endl;
return 0;
}
Program outputs:
A. 1 3 5 7 9 ?1 ?3 ?5 ?7 ?9
B. 9 7 5 3 1 ?1 ?3 ?5 ?7 ?9
C. ?9 ?7 ?5 ?3 ?1 1 3 5 7 9
D. 1 3 5 7 9 ?1 ?3 ?5 ?7 ?9
E. ?1 ?3 ?5 ?7 ?9 9 7 5 3 1
Answer: B

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