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NEW QUESTION: 1
Your network contains an Active Directory forest. The forest contains a single domain named contoso.com.
The network contains a legacy mail system that uses a SMTP namespace of contoso.com.
You plan to deploy Exchange Server 2013.
There will be a period of interoperability while the email is migrated from the legacy system to Exchange Server 2013.
During the period of interoperability, you need to ensure that all incoming email is received by an Exchange Server 2013 server, and then routed to the legacy mail system if an Exchange Server email recipient cannot be found.
You configure the firewall in the perimeter network to route SMTP traffic to the Exchange Server 2013 organization.
What should you do next?
A. Modify the existing accepted domain for contoso.com and create a new Send connector.
B. Add a new authoritative domain for contoso.com and create a new email address policy.
C. Add a new internal relay accepted domain for contoso.com and create a new email address policy.
D. Add a new external relay accepted domain for contoso.com and create a new Send connector.
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Step 1: Modify accepted domain for contoso.com and make it an internal relay domain.
Step 2: Create a new send connector which routes mail for the contoso.com namespace to the legacy namespace - if a recipient cannot be found in the Exchange org.
References:

NEW QUESTION: 2
ネットワーク技術者が488台のホストマシン用に新しいサブネットを作成しています。技術者は、サブネットを作成するときにクラスBアドレススキームを使用するように指示され、同じサイズの追加サブネットに対して可能な限り多くのスペースを残すように指示されます。これらの要件を満たすサブネットはどれですか？
A. 192.168.25.0/24
B. 10.233.2.0/23
C. 172.16.0.0/22
D. 10.5.4.0/22
E. 172.18.0.0/23
Answer: E

NEW QUESTION: 3
IPアドレス10.16.3.65/23を説明する2つのステートメントはどれですか？ （2つ選択してください。）
A. サブネットアドレスは10.16.3.0 255.255.254.0です。
B. ネットワークはサブネット化されていません。
C. サブネット内の最後の有効なホストアドレスは10.16.2.254 255.255.254.0です
D. サブネット内の最小のホストアドレスは10.16.2.1 255.255.254.0です。
E. サブネットのブロードキャストアドレスは10.16.3.255 255.255.254.0です。
Answer: D,E
Explanation:
The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 - 254). So this makes the subnets in 0,
2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet. The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are 2.1 through
3.254

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