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NEW QUESTION: 1
QoS輻輳管理用語を左側から右側の説明にドラッグアンドドロップします。

Answer:
Explanation:

NEW QUESTION: 2
버킷 정책 중 '데모'라는 버킷에 업로드되는 개체가 암호화되도록 보장하는 버킷 정책은 무엇입니까?
Answer:
Explanation:
"s3 : x-amz-server-side-encryption": "aws : kms"조건은 업로드 된 개체를 암호화해야합니다.
ns3 : x-amz-server-side-encryption "조건을 보장해야하기 때문에 옵션 B, C 및 D가 유효하지 않습니다."aws : kms "가 있음 AWS KMS 모범 사례에 대한 자세한 내용을 보려면 아래에서 URL :
https://dl.awsstatic.com/whitepapers/aws-kms-best-praaices.pdf

전문가에게 피드백 / 검색어 제출

NEW QUESTION: 3
Sie entwickeln eine Microsoft SQL Server 2012-Datenbank, die Tabellen mit den Namen Employee und Person enthält.
Die Tabellen haben folgende Definitionen:

Benutzer können in dieser Ansicht einzelne INSERT-Anweisungen oder INSERT ... SELECT-Anweisungen verwenden.
Sie müssen sicherstellen, dass Benutzer mithilfe der Ansicht "VwEmployee" mit einer einzigen Anweisung Datensätze in die Tabellen "Employee" und "Person" einfügen können.
Welche Transact-SQL-Anweisung sollten Sie verwenden?
A. CREATE TRIGGER TrgVwEmployee
ON VwEmployee
STATT EINFÜGEN
WIE
START
INSERT INTO Person (ID, Vorname, Nachname)
SELECT ID, Vorname, Nachname FROM VwEmployee
INSERT INTO Employee (PersonID, EmployeeNumber)
SELECT Id, EmployeeNumber FROM VwEmployee
Ende
B. CREATE TRIGGER TrgVwEmployee
ON VwEmployee
FÜR EINSATZ
WIE
START
INSERT INTO Person (ID, Vorname, Nachname)
SELECT ID, Vorname, Nachname, FROM eingefügt
INSERT INTO Employee (PersonId, EmployeeNumber)
SELECT Id, EmployeeNumber FROM eingefügt
ENDE
C. CREATE TRIGGER TrgVwEmployee
ON VwEmployee
STATT EINFÜGEN
WIE
START
DECLARE @ID INT, @FirstName NVARCHAR (25), @LastName NVARCHAR (25), @PersonID INT, @EmployeeNumber NVARCHAR (15) SELECT @ID = ID, @FirstName = Vorname, @LastName = Nachname, @EmployeeNumber
= EmployeeNumber
FROM eingefügt
INSERT INTO Person (ID, Vorname, Nachname)
WERTE (@ID, @FirstName, @LastName)
INSERT INTO Employee (PersonID, EmployeeNumber)
WERTE (@PersonID, @EmployeeNumber
Ende
D. CREATE TRIGGER TrgVwEmployee
ON VwEmployee
STATT EINFÜGEN
WIE
START
INSERT INTO Person (ID, Vorname, Nachname)
SELECT ID, Vorname, Nachname, FROM eingefügt
INSERT INTO Employee (PersonId, EmployeeNumber)
SELECT Id, EmployeeNumber FROM eingefügt
ENDE
Answer: D

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