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NEW QUESTION: 1
次の設定を持つ2つのデータベースがあります。

次のTransact-SQLステートメントを実行します。

DiskTableからデータを選択し、そのデータをMemTableに挿入する必要があります。 即時の耐久性なしで明示的なトランザクションとしてMemTableへの挿入操作を完了する必要があります。
どの4つのTransact-SQLセグメントを使用する必要がありますか？ 回答するには、適切なTransact-SQLセグメントをTransact-SQLセグメントのリストから回答領域に移動し、正しい順序で配置します。

Answer:
Explanation:

Explanation

Box 1: BEGIN TRANSACTION
Box 2: UPDATE ... #Disktable
Box 3: IF... SELECT INTO ...#Disktable
Box 4: .. DELAYED_DURABILITY = ON
The COMMIT syntax is extended so you can force delayed transaction durability. If DELAYED_DURABILITY is DISABLED or FORCED at the database level (see above) this COMMIT option is ignored.
Syntax:
COMMIT [ { TRAN | TRANSACTION } ] [ transaction_name | @tran_name_variable ] ] [ WITH ( DELAYED_DURABILITY = { OFF | ON } ) ] References:
https://docs.microsoft.com/en-us/sql/relational-databases/logs/control-transaction-durability?view=sql-server-20

NEW QUESTION: 2
Which test run is more likely to profit from Run-time Settings being configured to General: Log > Always Send Messages > Extended Log > Parameter Substitution?
A. debug test
B. full load test
C. scalability test
D. top time test
Answer: A

NEW QUESTION: 3
DRAG DROP




Answer:
Explanation:
Box 1:

Box 2:

Box 3:

Note:
Use > for greater than comparison.
Use < for less than comparison.

NEW QUESTION: 4
Examine the commands used to create the DEPARTMENT_DETAILS and the COURSE- DETAILS tables:
SQL> CREATE TABLE DEPARTMfiNT_DeTAILS
DEPARTMENT_ID NUMBER PRIMARY KEY ,
DEPARTMEHT_NAME VARCHAR2(50) ,
HOD VARCHAP2(50));
SQL> CREATE TABLE COURSE-DETAILS
(COURSE ID NUMBER PRIMARY KEY ,
COURS_NAME VARCHAR2 (50) ,
DEPARTMEHT_ID NUMBER REFERENCES DEPARTMENT_DETAIL
You want to generate a list of all department IDs along with any course IDs that may have been assigned to them.
Which SQL statement must you use?
A. SELECT d.department id. ccours_id FROM department_details d RIGHT OUTER JOIN course_details c ON (d.department_id);
B. SELECT d.department_id, c.course_id FROM department_details d LEFT OUTER JOIN course_details c ON (d.department___id).- (DEPARTMENT_ID) ;
C. SELECT d.departranc_id, c.course_id FROM cource_deatils c LEFT OUTER JOIN departmnt_details d ON (c.dapartmsnt_id=d.departtnent_id);
D. SELECT d.department_id, c. course_id FROM dapartment_details d RIGHT OUTER JOIN course_dotails c ON (c.depattnient_id=d.department_id) ;
Answer: B

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