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NEW QUESTION: 1
Assume that a Product element has a Price Per Unit attribute, and the content model includes one Price element. Select which of the following correctly describes the XML Schema definition content. Assume the Schema namespace prefix is "xs".
A. <xs:element name="Product">
<xs:complexType>
<xs:sequence>
<xs:element name="Price" type="xs:string"/>
</xs:sequence>
<xs:attribute name="PricePerUnit" type="xs:string"/>
</xs:complexType>
</xs:element>W Courier Newlr Z
B. <xs:element name="Product">
<xs:complexType>
<xs:sequence>
<xs:attribute name="PricePerUnit" type="xs:string"/>
<xs:element name="Price" type="xs:string"/>
</xs:sequence>
</xs:complexType>
</xs:element>
C. <xs:element name="Product">
<xs:complexType>
<xs:attribute name="PricePerUnit" type="xs:string"/>
<xs:sequence>
<xs:element name="Price" type="xs:string"/>
</xs:sequence>
</xs:complexType>
</xs:element>
D. <xs:element name="Product">
<xs:complexType>
<xs:sequence>
<xs:element name="Price" type="xs:string"/>
<xs:attribute name="PricePerUnit" type="xs:string"/>
</xs:sequence>
</xs:complexType>
</xs:element>
Answer: A

NEW QUESTION: 2
A UNIX administrator notifies the storage administrator that extra LUNs can be seen on a UNIX server. The LUNs appear to be NTFS file systems. Which of the following MOST likely happened?
A. The NTFS LUNs are snapshots.
B. The UNIX server is multipathed.
C. The HBA allocation is wrong.
D. The iSCSI initiator was not restarted.
Answer: C

NEW QUESTION: 3
View the exhibit and examine the structure in ORDERSand ORDER_ITEMStables.

You need to create a view that displays the ORDER_ID, ORDER_DATE, and the total number of items in each order.
Which CREATEVIEWstatement would create the views successfully?
A. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date;
B. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id) ||
" NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date
WHITH CHECK OPTION;
C. CREATE OR REPLACE VIEW ord_vu
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
" NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date;
D. CREATE OR REPLACE VIEW ord_vu (order_id, order_date)
AS SELECT o.order_id, o.order_date, COUNT (i.line_item_id)
" NO OF ITEMS"
FROM orders o JOIN order_items i
ON (o.order_id = i.order_id)
GROUP BY o.order_id, o.order_date;
Answer: C

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