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NEW QUESTION: 1
A Solutions Architect is building an application that stores object data. Compliance requirements state that the data stored is immutable.
Which service meets these requirements?
A. AWS Storage Gateway
B. Amazon S3
C. Amazon Glacier
D. Amazon EFS
Answer: C
Explanation:
Explanation/Reference:
Explanation
Data stored in Amazon Glacier is immutable, meaning that after an archive is created it cannot be updated.
This ensures that data such as compliance and regulatory records cannot be altered after they have been archived.
Reference https://aws.amazon.com/glacier/features/

NEW QUESTION: 2
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to run a query to find the total number of customers who have both deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
EXCEPT
SELECT CustNo
FROM tblLoanAcct) R
B. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
UNION
SELECT CustNo
FROM tblLoanAcct) R
C. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
WHERE D.CustNo IS NULL OR L.CustNo IS NULL
D. SELECT COUNT(*)
FROM (SELECT AcctNo
FROM tblDepositAcct
INTERSECT
SELECT AcctNo
FROM tblLoanAcct) R
E. SELECT COUNT (DISTINCT D.CustNo)
FROM tblDepositAcctD, tblLoanAcct L
WHERE D.CustNo = L.CustNo
F. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
UNION ALL
SELECT CustNo
FROM tblLoanAcct) R
G. SELECT COUNT(DISTINCT L.CustNo)
FROM tblDepositAcct D
RIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNo
WHERE D.CustNo IS NULL
H. SELECT COUNT(*)
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
Answer: D
Explanation:
Explanation/Reference:
Explanation:
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php

NEW QUESTION: 3
Examine these statements:

Which two corrections will allow this anonymous block to execute successfully?
A. Add wk# .NEXT; before the 7thline.
B. Replace lines 5 and 6 with wk# (i) := tp_rec# (i, i);
C. Add i PLS_INTEGER; before the 3rdline.
D. Change line #2 to wk# tp_test# := tp_test# (tp_rec# ());
E. Add wk#. EXTEND (1); before the 5thline.
Answer: B,E

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